L'Hospital's Rule Step by Step Examples for Indeterminate Forms

I'm really stuck on L'Hopital's Rule for my calculus class. My professor went through it quickly, and I'm still not getting how to apply it to different indeterminate forms. I need some super clear, worked-out examples to finally understand it for my upcoming exam.

1 Answers

✓ Best Answer

🤔 What is L'Hôpital's Rule?

L'Hôpital's Rule states that if the limit of $f(x)/g(x)$ as $x$ approaches $c$ results in an indeterminate form (0/0 or ∞/∞), then:

$\lim_{x \to c} \frac{f(x)}{g(x)} = \lim_{x \to c} \frac{f'(x)}{g'(x)}$

provided the limit on the right exists.

📝 Steps to Apply L'Hôpital's Rule

  1. Verify Indeterminate Form: Check if the limit results in 0/0 or ∞/∞.
  2. Differentiate: Find the derivatives of the numerator $f'(x)$ and the denominator $g'(x)$.
  3. Evaluate the New Limit: Compute the limit of $f'(x)/g'(x)$ as $x$ approaches $c$.
  4. Repeat if Necessary: If the new limit is still an indeterminate form, repeat steps 2 and 3.

🚀 Example 1: 0/0 Form

Evaluate: $\lim_{x \to 0} \frac{\sin(x)}{x}$

  1. Verify Indeterminate Form: As $x \to 0$, $\sin(x) \to 0$ and $x \to 0$, so we have 0/0.
  2. Differentiate:
    • $f(x) = \sin(x) \implies f'(x) = \cos(x)$
    • $g(x) = x \implies g'(x) = 1$
  3. Evaluate the New Limit:

    $\lim_{x \to 0} \frac{\cos(x)}{1} = \frac{\cos(0)}{1} = \frac{1}{1} = 1$

Therefore, $\lim_{x \to 0} \frac{\sin(x)}{x} = 1$

♾️ Example 2: ∞/∞ Form

Evaluate: $\lim_{x \to \infty} \frac{x^2}{e^x}$

  1. Verify Indeterminate Form: As $x \to \infty$, $x^2 \to \infty$ and $e^x \to \infty$, so we have ∞/∞.
  2. Differentiate (First Application):
    • $f(x) = x^2 \implies f'(x) = 2x$
    • $g(x) = e^x \implies g'(x) = e^x$

    $\lim_{x \to \infty} \frac{2x}{e^x}$

  3. Verify Indeterminate Form Again: As $x \to \infty$, $2x \to \infty$ and $e^x \to \infty$, so we still have ∞/∞.
  4. Differentiate (Second Application):
    • $f'(x) = 2x \implies f''(x) = 2$
    • $g'(x) = e^x \implies g''(x) = e^x$

    $\lim_{x \to \infty} \frac{2}{e^x}$

  5. Evaluate the New Limit:

    $\lim_{x \to \infty} \frac{2}{e^x} = 0$

Therefore, $\lim_{x \to \infty} \frac{x^2}{e^x} = 0$

⚠️ Important Notes

  • L'Hôpital's Rule only applies to indeterminate forms 0/0 and ∞/∞.
  • Ensure that both $f(x)$ and $g(x)$ are differentiable.
  • Sometimes, you may need to apply the rule multiple times.

Know the answer? Login to help.