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βΎοΈ Infinite Geometric Series: A Deep Dive
An infinite geometric series is the sum of an infinite number of terms that have a constant ratio between successive terms. Understanding when these series converge (approach a finite value) or diverge (grow without bound) is crucial. Let's explore this concept in detail.
π€ Convergence vs. Divergence
The behavior of an infinite geometric series depends on its common ratio, denoted as 'r'.
- Convergence: If the absolute value of the common ratio is less than 1 (i.e., |r| < 1), the series converges. This means the sum approaches a finite value.
- Divergence: If the absolute value of the common ratio is greater than or equal to 1 (i.e., |r| β₯ 1), the series diverges. This means the sum does not approach a finite value and grows indefinitely.
π Formula for the Sum of a Convergent Infinite Geometric Series
When an infinite geometric series converges, we can calculate its sum using the following formula:
$$S = \frac{a}{1 - r}$$
Where:
- $S$ is the sum of the infinite series.
- $a$ is the first term of the series.
- $r$ is the common ratio (and |r| < 1 for convergence).
βοΈ Examples
Example 1: Convergent Series
Consider the series: 1 + 1/2 + 1/4 + 1/8 + ...
Here, $a = 1$ and $r = 1/2$. Since |1/2| < 1, the series converges. Let's find its sum:
$$S = \frac{1}{1 - \frac{1}{2}} = \frac{1}{\frac{1}{2}} = 2$$
Thus, the sum of the series is 2.
Example 2: Divergent Series
Consider the series: 1 + 2 + 4 + 8 + ...
Here, $a = 1$ and $r = 2$. Since |2| β₯ 1, the series diverges. It does not have a finite sum.
Example 3: Another Convergent Series
Consider the series: 5 - 5/3 + 5/9 - 5/27 + ...
Here, $a = 5$ and $r = -1/3$. Since |-1/3| < 1, the series converges. Let's find its sum:
$$S = \frac{5}{1 - (-\frac{1}{3})} = \frac{5}{\frac{4}{3}} = \frac{15}{4}$$
Thus, the sum of the series is 15/4 or 3.75.
π» Code Example (Python)
Here's a Python code snippet to calculate the sum of a convergent geometric series:
def geometric_sum(a, r, n_terms):
if abs(r) >= 1:
return "Series diverges"
else:
return a / (1 - r)
# Example usage:
first_term = 1
common_ratio = 0.5
sum_of_series = geometric_sum(first_term, common_ratio, 100) #using 100 terms to approximate infinite series
print(f"The sum of the infinite geometric series is: {sum_of_series}")
π‘ Key Takeaways
- Infinite geometric series converge only when the absolute value of the common ratio is less than 1 (|r| < 1).
- The sum of a convergent infinite geometric series can be found using the formula $S = \frac{a}{1 - r}$.
- Divergent geometric series do not have a finite sum.
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